Respuesta :
His image is formed at a 0.75m distance from the mirror while the focal length and the radius of curvature are 1.00m and 2.00m respectively.
- To calculate the image distance you can use the formula for the mirror's magnification which is,
[tex]\begin{aligned}\\\\M&=\frac{V}{U}\end{aligned}[/tex]
- Here V and U represent the image distance and the object distance measured from the mirror's centre.
- Therefore,
[tex]\begin{aligned}\\\\0.25&=\frac{V}{3.00\,m}\\\\V&=0.75\,m\end{aligned}[/tex]
- For the second part, you can use the lens formula as you know V and U now, as follows.
[tex]\begin{aligned}\\\\\frac{1}{V}+\frac{1}{U}&=\frac{1}{f}\\\frac{1}{-0.75}+\frac{1}{3.00} &=\frac{1}{-f}\\f&=1.00\,m\end{aligned}[/tex]
- For the final part, you should know that the radius of curvature is twice the focal length for these curvy optics. Therefore,
[tex]\begin{aligned}\\\\R&=2f\\&=2.00\,m\end{aligned}[/tex]
- To know more about convex mirrors and their properties follow the link below.
https://brainly.com/question/23864253?
His image forms at 0.75m. The focal length of the mirror is 1.00m and the radius if curvature is 2.00m.
a) To calculate the image distance,
m=v/u where m is magnification, v is image distance and u is object distance.
Therefore,
0.25=v/3.00
v=0.75m
b) To calculate the focal length using the lens formula,
1/v+1/u=1/f
Therefore,
1/-0.75 + 1/3.00 =1/f
f=1.00m
c) The radius of curvature is twice the focal length.
Therefore,
R=2f
R=2.00m
read more about reflection around curved mirrors from:
https://brainly.com/question/29568154
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