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a bird is flying with a speed of 16.6 m/s over water when it accidentally drops a 2.10 kg fish. the acceleration of gravity is 9.81 m/s 2 . if the altitude of the bird is 7.20 m and air resistance is disregarded, what is the speed of the fish when it hits the water?]

Respuesta :

The speed of the fish is 20.411 m/s

We are given that,

Initial speed = u =16.6m/s

Mass of fish = m = 2.10kg

Altitude of the bird = h = 7.20m

Acceleration due to to gravity = a = 9.8m/s²

Thus equation of motion can be given by the formula ,

h = ut + (1/2)at²

If taking initial velocity is zero then ut = 0, thus above equation can be written as,

t² = (2 × 7.20m)/9.8m/s²

t² = 1.469s

t = 1.212 sec

Then the vertical velocity after 1.212sec can be calculated as,

Vy = u + gt

Vy = 0 + 9.8m/s²× 1.212sec

Vy = 11.8776m/s

Horizontal velocity will be same as the initial velocity,

Vnet = √u² +V²y

Vnet = √(16.6m/s)²+(11.8776m/s)²

Vnet = 20.411 m/s

Therefore , the speed of the fish would be 20.411m/s

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