Answer:
- (x^2 -81) : a = 1, b = 0, c = -81
- (x^2 -4) : a = 1, b = 0, c = -4
- (36x^2 -25) : a = 36, b = 0, c = -25
- (49x^2 -1) : a = 49, b = 0, c = -1
Step-by-step explanation:
You want the values of a, b and c in the quadratics (x^2 -81), (x^2 -4), (36x^2 -25), and (49x^2 -1).
Coefficients
Each of these quadratics is the difference of squares. It has the form ...
ax^2 +c
where both 'a' and '-c' are perfect squares. The coefficient 'b' is zero.
- (x^2 -81) : a = 1, b = 0, c = -81
- (x^2 -4) : a = 1, b = 0, c = -4
- (36x^2 -25) : a = 36, b = 0, c = -25
- (49x^2 -1) : a = 49, b = 0, c = -1
