The rotation around the origin results in the transformation of AB to form A'B' would be 180.
How does rotation by 90 degrees changes the coordinates of a point if rotation is with respect to origin?
Let the point be having coordinates (x,y).
Case 1: If the point is in the first quadrant:
Subcase: Clockwise rotation:
Then (x,y) → (y, -x)
Subcase: Counterclockwise rotation:
Then (x,y) → (-y, x)
Case 2: If the point is in the second quadrant:
Subcase: Clockwise rotation:
Then (x,y) → (y, -x)
Subcase: Counterclockwise rotation:
Then (x,y) → (-y, x)
Case 3: If the point is in third quadrant:
Subcase: Clockwise rotation:
Then (x,y) → (y, -x)
Subcase: Counterclockwise rotation:
Then (x,y) → (-y, x)
Case 4: If the point is in the fourth quadrant:
Subcase: Clockwise rotation:
Then (x,y) → (y, -x)
Subcase: Counterclockwise rotation:
Then (x,y) → (-y, x)
Case 5: On the origin
No effect as we assumed rotation is being with respect to the origin.
Line AB is rotated to form A'B' .
The coordinates of point A are (1,5) and the coordinates of point B are (−6,4).
The rotation around the origin results in the transformation of AB to form A'B' would be 180.
Learn more about the rotation of a point with respect to origin here:
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