Answer:
Option (c) is correct .
The base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is [tex]=\frac{1}{2}[/tex]
Step-by-step explanation:
Given : base = twice its hypotenuse
that is ,
Consider hypotenuse be x then base will be 2x .
Consider the right angled triangle in figure below with right angle at B and base BC.
∠A is the angle opposite to the base.
[tex]\text sinA=\frac{\text Perpendicular}{\text Hypotenuse}[/tex]
[tex]\text sinA=\frac{BC}{AC}[/tex]
[tex]\text sinA=\frac{x}{2x}[/tex]
[tex]\text sinA=\frac{1}{2}[/tex]
Thus, For the base of a triangle is twice its hypotenuse, the sine of the angle opposite to its base is [tex]=\frac{1}{2}[/tex]
