A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?

Respuesta :

First, we determine the acceleration by using the given initial and final velocities and the time.
                               acceleration = (153 m/s - 58 m/s) / 12 s 
                                                      = 7.917 m/s²
Then, use the equation below to solve for the distance. 
                                 distance = (V² - v²) / 2a
where V is the final velocity, v is the initial velocity and a is the acceleration. Substituting,
                                   d = (153² - 58²) / 2(7.917)
                                      = 1266 m
Thus, the spaceship have traveled 1,266 m.