Respuesta :
as you said it was dropped so in that case I'll take 78.4 meters as the height..
we know that
h = ut + 0.5*g*t(sqr)
t(sqr) = 78.4/(0.5*9.8) [g = 9.8 ms-2]
t = √16
t = 4
So it'd take 4 seconds
we know that
h = ut + 0.5*g*t(sqr)
t(sqr) = 78.4/(0.5*9.8) [g = 9.8 ms-2]
t = √16
t = 4
So it'd take 4 seconds
Answer:
The time is 4 sec.
Step-by-step explanation:
Given that,
Distance = 78.4 m
We need to calculate the time
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
[tex]t =\sqrt{\dfrac{2s}{g}}[/tex]
Where, s = distance
g = acceleration due to gravity
t = time
[tex]t =\sqrt{\dfrac{2\times78.4}{9.8}}[/tex]
[tex]t=4\ sec[/tex]
Hence, The time is 4 sec.