Respuesta :

Atomic mass of hydrogen= 1 u
Atomic mass of oxygen = 16 u
Molecular mass of water=1*2+16*1
=18 u
Mass of 1 mole of water= 18 g=0.018 kg
KE=1/2mv²
=1/2*0.018*11.7²
=1.23 J (approx.)

Answer:

[tex]k=1.23J[/tex]

Explanation:

1. The equation to calculate the kinetic energy is:

[tex]k=\frac{mv^{2} }{2}[/tex] (Eq.1)

where, m=mass, v=velocity, k=kinetic energy

2. Find the mass of one mole of water, [tex]H_{2}O[/tex]:

Atomic weight of H = 1[tex]\frac{g}{mol}[/tex]

Atomic weight of O = 16[tex]\frac{g}{mol}[/tex]

Molecular weight of [tex]H_{2}O[/tex] = (2*1) + 16

Molecular weight of [tex]H_{2}O[/tex] = 18[tex]\frac{g}{mol}[/tex]

3. Convert the mass of [tex]H_{2}O[/tex] from g to Kg:

[tex]18g*\frac{1Kg}{1000g}=0.018Kg[/tex]

3. Replace quantities in Eq.1:

[tex]k=\frac{0.018g*(11.7\frac{m}{s})^{2}}{2}[/tex]

[tex]k=1.23J[/tex]