Respuesta :
surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft, can be solved by solving the area of each face of a cube. since the cube has 6 faces and all the faces are congruent because it all has the same edge.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
Surface area of a cube is sum of area of its sides. The surface area of the considered cube shaped tank is 311.04 sq. feet.
How to find the surface area of a cube?
A cube has all sides congruent, so its all sides have same area.
Supposing that the considered cube has side length (also called edge length) of L units.
Then, its one side's area equals [tex]L^2[/tex] sq. units (as each side is a square, so we used formula for area of a square).
Since there are 6 such sides in a closed cube, thus, its surface area evaluates to
[tex]S = L^2 + L^2 + ... + L^2 \text{\: (six times)} = 6L^2 \: \rm unit^2[/tex]
For the given case, we have:
Edge length of the cube shaped closed tank = 7.2 ft.
Thus, its surface area evaluates to :
[tex]S = 6L^2 = 6 \times (7.2)^2 = 311.04 \: \rm ft^2[/tex]
Thus, the surface area of the considered cube shaped tank is 311.04 sq. feet.
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