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Solve the trigonometric equation for the variable x:
2
cos(x) = ——
5
Take the inverse cosine function of both sides, then you get
[tex]\mathsf{x=\pm\,arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°}[/tex]
[tex]\mathsf{x=-\,arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°~~~or~~~x=arccos\!\left(\dfrac{2}{5}\right)+k\cdot 360\°}[/tex] ✔
(exact form)
x ≈ 66.42° + k · 360° or x ≈ – 66.42° + k · 360° ✔
(approximate form)
where k is an integer.
I hope this helps. =)
Tags: trigonometric trig equation cosine cos arccos solve trigonometry