Data:
Molar Mass of NaOH = 40 g/mol
Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules
6.02*10²³y = 0.270*10²³
[tex]y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}} [/tex]
[tex]\boxed{y \approx 0.04\:mol}[/tex]
Solving: Find the mass value now
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH
[tex]x = 40*0.04[/tex]
[tex]\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark[/tex]
Answer:
The mass is 1.6 grams
