Respuesta :

y = a (x - 2)^2 + 13............vertex form y= a(x - h)^2 + k...with vertex (h, k) 

5 = a(0 -2)^2 + 13 
5= 4a + 13 
- 8 = 4a 
-2 = a 

y = -2 (x - 2)^2 + 13........now let y=0 and find the x intercept 

0 = -2(x - 2)^2 + 13...........subtract 13 

-13= -2(x - 2)^2................divide by -2 

-13/-2 = (x - 2)^2.............simplify 

13/2 = (x - 2)^2............take the sq rts. 

√(13/2) = x - 2..............√6.5 =2.55........add 2 

x = 4.55

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