A 3m ladder stands on horizontal ground and reaches 2.8 m up a vertical wall. how far is the foot of the ladder from the base of the wall? round your answer to the nearest hundredth.

1.08 m. is the answer because you would use the pythagorean theorem to solve it.
2.8^2+b^2=3^2
7.84+b^2=9
b^2=9-7.84
square root of b^2=square root of 1.16
b=1.08

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ap8997154 ap8997154 · Answer 2 · 2022-08-15T15:10:54+02:00

Pythagoras' theorem is a basic relationship between the three sides of a right triangle in Euclidean geometry. The distance between the base of the ladder and the wall is 1.08 meters.

What is Pythagoras theorem?

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The size of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides, according to this rule.

For the given situation a diagram is made as shown below. In the given diagram, triangle ABC is formed by the wall, ladder and the ground.

Using the Pythagoras theorem the distance between the base of the ladder and the wall can be found as shown below,

AC² = AB² + BC²

(3 meters)² = (2.8 meters)² + (BC)²

9 = 7.84 + BC²

BC² = 9 - 7.84

BC² = 1.16

BC = √1.16

BC = 1.08 meters

Hence, the distance between the base of the ladder and the wall is 1.08 meters.

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