Let x be the amount in L of the 20% acid and y be the amount in L of the 60% acid. Doing an overall volume balance,
V = x + y = 30
Then, doing an alcohol balance,
0.2x + 0.60y = (30)(0.5)
The values of x and y from the generated equations above are
x = 7.5L
y = 22.5 L
Therefore, she will need 7.5L of 20% acid solution and 22.5L of 60% acid solution.