Respuesta :

williamwu309
if dy / dt = 1, then y = t. If y = t, then y = 2/3, and then you could do 3 /2/3, getting us 3/2
[tex]\bf xy=2\implies y=\cfrac{2}{x}\\\\ -----------------------------\\\\ \cfrac{dx}{dt}\cdot y\quad +\quad x\cdot \cfrac{dy}{dt}=0\implies \cfrac{dx}{dt}=-\cfrac{x}{y}\cdot \cfrac{dy}{dt} \\\\\\ \textit{now, we know that } \begin{cases} \frac{dy}{dt}=1\\ x=3\\ y=\frac{2}{x} \end{cases}\qquad thus \\\\\\ \cfrac{dx}{dt}=-\cfrac{3}{\frac{2}{3}}\cdot 1\implies \cfrac{dx}{dt}=-\cfrac{9}{2}[/tex]

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