Please help me with this problem!!


Jordan has a photograph is 3 inches shorter than its length. The perimeter of the photograph is 22 inches. Jordan went to a photo shop to have the length of the photo tripled. What is the length of the enlarged photograph?

Respuesta :

 4 sides
3 by 3
8 by 8
so it would be 8 
because 8 is how long it is 

Hope this helps :)

The length of the enlarged photo would be 21 in.

For the original picture, we can represent the length as x and the width as x-3. Then we can use the perimeter equation: p=2w + 2l
 
22 = 2x + 2(x-3)
22 = 4x - 6
x = 7

Since the original length is 7 and the length is tripled, the new length is 21 in.