Answer: The answer is (c) f(x) = cos x and f(x) = sec x.
Step-by-step explanation: We are given four trigonometric functions out of we are to select those which have values greater than for 0 < x < π.
Since the values of sine and cosine functions lies between -1 and 1. So, they cannot go beyond 1 and hence option (a) and (b) are incorrect.
Since [tex]\tan \dfrac{\pi}{6}=\dfrac{1}{\sqrt 3},[/tex]
so we will have
[tex]\cot \dfrac{\pi}{6}=\sqrt {3}>1.[/tex]
So, option (c) is correct.
And, we know that
[tex]\cos \dfrac{\pi}{6}=\dfrac{\sqrt 3}{2},[/tex]
so we will have
[tex]\sec \dfrac{\pi}{6}=\dfrac{2}{\sqrt {3}}>1.[/tex]
So, this option is also correct.
Thus, (c) and (d) are the correct ones.
