Respuesta :
Answer: k=±`12
Step-by-step explanation:
[tex]ax^2-bx+c=0\\\\9x^2-kx+4=0\\\\D=b^2-4ac\\\\a=9\ \ \ \ b=-k\ \ \ \ c=4\\\\D=0\\\\Hence,\\\\D=(-k)^ 2-4(9)(4)=0\\\\k^2-144=0\\\\k^2=144\\\\k^2=12^2[/tex]
Extract the square root of both parts of the equation:
[tex]k=б\sqrt{12^2} \\\\k=б12[/tex]
Answer:
- k = - 12 or k = 12
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A perfect square trinomial is:
- (a ± b)² = a² ± 2ab + b²
Given trinomial:
- 9x² - kx + 4 = 0
Show this as:
- (±3x)² - kx + (±2)² = 0
Compare and find possible values of k:
- k = - 2(±3)(±2) = ± 12