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The width of a rectangle is w feet. The length of the rectangle is six less than three times
the width. Write an algebraic expression that represents the area, in square feet, of the
rectangle in terms of w.

Respuesta :

Answer:

Area = 3w^2 - 6w

Step-by-step explanation:

Area = width * length

width = w

length = 3w - 6

  • this is because the length is six less than three times the width so you get that the length = 3w - 6

Area = w (3w - 6)

Area = 3w^2 - 6w

devishri1977

Answer:

Area of rectangle = 3w² - 6w

Step-by-step explanation:

Framing algebraic expressions:

      Width = 'w' ft

      three times of width = 3*w = 3w

             six less than 3w = 3w - 6

   length = 3w - 6

     [tex]\sf \boxed{\bf Area \ of \ rectangle = length*width}[/tex]

                                      = (3w - 6)*w

                                      = 3w*w - 6*w

                                      = 3w² - 6w

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