Luis has 60 m of fencing to build a four-sided fence around a rectangular plot of land. The area of the land is 216 square meters. Solve for the dimensions (length and width) of the field. The dimensions are __ meters by __ meters .

Respuesta :

The dimensions are 18 m by 12 m

We can solve this by using quadratic equations.

First let's see what is given in the question

The perimeter of the rectangle = 60 m = 2(l+b)

The area of the rectangle           =  216 m =  l×b

                                       2(l+b) = 60

                                        l+b = 60÷2 = 30

                                        b = 30-l...........eq.1

                       

    area, l×b= 216................................eq.2

applying eq.1 in eq.2

    l×(30-l) = 216

30l-l² = 216

30l-l²-216 = 0

multiplying by -1

l²-30l+216 = 0

So while solving this quadratic equation

Sum of two number will be -30 and Product will be 216

such two numbers are -12 and -18

Since negative values cannot be sides of the rectangles the sides are 18m and 12m

For further references about quadratic equations, please refer

https://brainly.com/question/1863222