Note¹: One integer is 6/6 of the wall
Note²: Make the rule of three simple
ton __ Coverage
[tex] \frac{2}{5} [/tex] --------------- [tex] \frac{5}{6} [/tex]
y --------------- [tex] \frac{6}{6} [/tex]
Solving: (directly proportional)
[tex] \frac{ \frac{2}{5} }{y}= \frac{ \frac{5}{6} }{ \frac{6}{6} } [/tex]
Product of extremes equals product of means
[tex] \frac{5}{6} *y = \frac{2}{5} * \frac{6}{6} [/tex]
[tex]\frac{5y}{6} = \frac{12}{30} [/tex]
Product of extremes equals product of means
[tex]5y*30 = 6*12[/tex]
[tex]150y = 72[/tex]
[tex]y = \frac{72}{150} \frac{\div6}{\div6} \to \boxed{\boxed{y = \frac{12}{25} }}\end{array}}\qquad\quad\checkmark[/tex]
Answer:
[tex] \frac{12}{25}\:\textbf{ton\:of\:concrete} [/tex] or 0.48 ton of concrete
