The acute angle that has a cosine of 4/5 is angle B
SOH CAH TOA identity
From the given diagram;
Hypotenuse = 10
Considering the angle <A
Adjacent = 6
cos <A = adj/hyp
cos<A = 6/10
cos<A = 3/5
Considering the angle <B
Adjacent = 8
cos <B = adj/hyp
cos<B = 8/10
cos<B = 4/5
Hence the acute angle that has a cosine of 4/5 is angle B
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