Answer: The true statement is (A) P(extra large)≈0.25.
Step-by-step explanation: Given that a piece of paper is randomly selected from a stack that contains 15 small, 44 large, and 20 extra large pieces.
We are to select the true statement.
Let S be the sample space for the experiment of choosing a piece.
Then, n(S) = 15 + 44 + 20 = 79.
Let A, B and C denote the events of choosing a small piece, a large piece and an extra large piece respectively.
So, n(A) = 15, n(B) = 44 and n(C) = 20.
Therefore, we have
[tex]P(\textup{small})=P(A)=\dfrac{n(A)}{n(S)}=\dfrac{15}{79}=0.1898\sim 0.19,\\\\\\P(\textup{large})=P(B)=\dfrac{n(B)}{n(S)}=\dfrac{44}{79}=0.5569\sim 0.56,\\\\\\P(\textup{extra large})=P(C)=\dfrac{n(C)}{n(S)}=\dfrac{20}{79}=0.2531\sim 0.25.[/tex]
Thus, the true statement is P(extra large)≈0.25.
Option (A) is correct.
