A right rectangular prism has a length of 10 in., a width of 12 in., and a height of 16 in. The dimensions of the prism are halved.


What is the surface area of the reduced prism?


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__in²

Respuesta :

The surface area of a rectangular prism can be found by adding the area of all sides together. To start, we will have to find the dimensions for the new prism, which is 5 * 6 * 8.

Then, we will have to find the area for each side. One of the sides will have 8*6, another 8*5, and the last 5*6.
We will then have 48, 40, and 30. Multiply them all by 2 and add them all together.
You will receive the final answer of 236 square inches.

The surface area of the reduced prism is 236 in².

Area

Area is the amount of space occupied by a two dimensional object or figure.

The surface area (A) of a rectangular prism is given by:

A = 2(lw + lh + hw)

where l = length, w = width and h = height.

The dimensions of the prism are halved, hence:

l = 10 in./2 =5 in., w = 12 / 2 = 6 in., h = 16 / 2 = 8 in.

Hence:

A = 2(5 * 6 + 5 * 8 + 8 * 6) = 236 in²

The surface area of the reduced prism is 236 in².

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