The value of QS of a parallelogram PQSR with perimeter 74 cm is 6cm
Properties of a parallelograms
- opposite sides are equal to each other
- opposite side are parallel to each other
Therefore,
4x - 1 = 3x + 7
subtract 3x from both sides
4x - 3x - 1 = 3x - 3x + 7
x - 1 = 7
add 1 to both sides of the equation
x - 1 + 1 = 7 + 1
x = 8
Therefore,
PQ = RS = (3(8) + 7) = 31 cm
Therefore,
74 = 2l + 2w
74 = 2(31) + 2w
74 - 62 = 2w
12 = 2w
w = 12 / 2
w = 6 cm
Therefore, QS = 6 cm
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