Respuesta :
lar mass of Ca = 40.08 grams/mole 77.4 g Ca * ( 1 mole Ca/ 40.08 ... n = m / M 1mol Caweights 40 gmol-1 n = 77,4 / 40 = 1.93 mol.
Answer: 1.94 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
Given mass = 77.4 g
Molar mass = 40 g/mol
Putting in the values:
[tex]\text{Number of moles}=\frac{77.4g}{40g/mol}=1.94[/tex]
Thus 1.94 moles of calcium atoms are there in 77.4 g of Ca.
