Answer:
Hence to the nearest tenth mean absolute deviation is:
2.3
Step-by-step explanation:
We are given a set of data points as:
The numbers of times she recorded were
0, 0, 0, 1, 3, and 8
on finding the mean we have:
[tex]Mean=\dfrac{0+0+0+1+3+8}{6}\\\\Mean=\dfrac{12}{6}\\\\Mean=2[/tex]
Hence, now we subtract each data point from mean and find their absolute value as:
|0-2|= 2
|0-2|=2
|0-2|=2
|1-2|=1
|3-2|=1
|8-2|=6
Hence now the mean of these absolute value is called Mean absolute Deviation (MAD)
[tex]MAD=\dfrac{2+2+2+1+1+6}{6}\\\\MAD=\dfrac{14}{6}\\\\MAD=2.333[/tex]
Hence to the nearest tenth mean absolute deviation is:
2.3
