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In kite ABCD, AB = BC and CD = DA. AB = (3x + 4), BC = x + 8, CD = y + 7, and DA = 2y + 5, find the perimeter of the kite

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jayshanaabreshayana
3x + 4 = x+ 8   >  3x - x = 2x   >  2x + 4 = 8 >  8 - 4 = 4 > 2x / 2 crosses out > 4 / 2 = 2 > x=2
2y + 5 = y + 7 >  2y - y = y >  y+ 5 = 7 >  7-5= 2 > y=2 
 
the perimeter of the kite is 4

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