Gary bought a car for $40,000. If V = 40,000(.85)t represents the value of the car after t years, how long will it take the car to be worth less than one-fourth of its purchase price?
40000*1/4=10000 10000=40000(0.85)^t solve for t t=log(10,000÷40,000)÷log(0.85) t=8.5 years Less than one-fourth Assume 9000 T=log(9,000÷40,000)÷log(0.85) T=9 years
