Kymani1118
contestada

I set a goal to drink 64 ounces of water day.If i drink 10 1/3 ounces in the morning,15 1/2 ounces at noon,and 20 5/6 at dinner how many more ounces of water do I have to drink to reach my goal

Respuesta :

melhunt99
First find how much you've had. Make the fractions with similar denominaters: 1/3(2)=2/6, 1/2(3)=3/6, 5/6(1)=5/6. Now add the fractions: 2/6+3/6+5/6=10/6 or 1 4/6 or 1 2/3. Then add the whole numbers: 10+15+20+1=46. So you've had 46 2/3 oz now subtract that from how much you need: 64-46 2/3= 63 3/3-46 2/3=17 1/3. You still need 17 1/3 water :)

The more ounces of water that should be drinking for reaching the goal is [tex]17 \frac{1}{3}[/tex] ounces.

Given that

The goal for drinking the water is 64 ounces.

If I drink  [tex]10 \frac{1}{3}[/tex]  ounces in the morning.

Drink  [tex]15 \frac{1}{2}[/tex]  ounces at noon.

And, [tex]20 \frac{5}{6}[/tex] ounces at dinner.

So,

The equation should be

[tex]= 64 - (10\frac{1}{3} - 15\frac{1}{2} - 20\frac{5}{6})\\\\= 64 - (\frac{31}{3} - \frac{31}{2} - \frac{125}{6})\\\\= 64 - (\frac{124 - 186 - 250 }{12}) \\\\= \frac{768 - 124 - 186 - 250}{12}\\\\= \frac{208}{12}\\\\= \frac{52}{3}\\\\= 17 \frac{1}{3}[/tex]

Therefore, we can conclude that The more ounces of water that should be drinking for reaching the goal is [tex]17 \frac{1}{3}[/tex] ounces.

Learn more about the ounces here: brainly.com/question/19833884

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