Try to find two point that land squarely on clear points. I'll use (-4,5) and (0,4)
The point slope form of a line is: y=mx+b where m is the slope and b is the y-intercept.
m=(y2-y1)/(x2-x1)=(4-5)/(0--4)
m=-1/4 we know b is 4 because of the point (0,4), but just for the sake of clarity... so far we have m so our line right now is:
y=-x/4 +b now we can use any point to solve for b, I'll use (-4,5) again...
5=--4/4 +b
5=1+b
b=4 so the line that produces that graph is:
y=-x/4 + 4 or more neatly...
y=(16-x)/4
