Answer:
28 g of AgNo3
Explanation:
800 g of 3.5% solution of AgNo3 is to be prepared.
3.5% AgNo3 solution contains 3.5g of AgNo3 in 100 g of solution.
If 3.5 g AgNo3 is present in 100 g of solution, then how many g is needed to make 800 g of solution?
3.5 g AgNo3..........................100 g solution
X g AgNo3.......................... 800 g solution
X g AgNo3 = 3.5 x 800/100
= 28 g
Hence, 28 g of AgNo3 will be required to prepare 800 g of 3.5% solution of AgNo3.
