This is NOT the case of adding up the sums of scores and dividing by 4.
This is a weighted average where we take each score and multiply by its weight (% worth) and then do the sum. We finally divide by sum of percentage (10%+15%+25%+50%=100%=1).
So, weighted average = [tex]\frac{(85*0.1)+(90*0.15)+(80*0.25)+(100*0.5)}{1} \\=\frac{92}{1}\\=92[/tex]
Joel's expected final average is D (92).
ANSWER: D
