Answer: The answer is [tex](B)~\sin A=\dfrac{48}{50},~~\cos A=\dfrac{14}{50}.[/tex]
Step-by-step explanation: We are given a right-angled triangle ABC, where ∠C = 90°, AC = 14 units, BC = 48 units and AB = 50 units.
For angle A,
hypotenuse, h = the longest side = AB,
base, b = adjacent side = AC
and
Perpendicular, p = side perpendicular to the base 'b' = BC.
Therefore, from ΔABC, we have
[tex]\sin A=\dfrac{p}{h}=\dfrac{BC}{AB}=\dfrac{48}{50},\\\\\cos A=\dfrac{b}{h}=\dfrac{AC}{AB}=\dfrac{14}{50}.[/tex]
Thus, (B) is the correct option that gives the ratio for sin A and cos A.
