Respuesta :

B-A=36
AB=max



B-A=36
add A to both sides
B=36+A
sub that for B in other equation
A(36+A)=max
distribute
A²+36A=max
take derivitive
2A+36=max'
set to zero to find A value
2A+36=0
2A=-36
A=-18

sub back

B=36+A
B=36-18
B=18

de numbers are -18 and 18
the product is 324

The two numbers A and B (with A≤B) whose difference is 36 and whose product is minimized are;

A = -18 and B = 18

Let the two numbers be A and B.

A ≤ B

Thus;

B - A = 36    ---(eq 1)

P = BA   ----(eq 2)

Making B the subject in eq 1 gives;  

B = 36 + A

put 36 + A for B in eq 2 to get;

P = A(36 + A)

P = A² + 36A

The values of A and B if their product is minimized is gotten by finding the derivative of the product and equating to zero to get;.

P' = 2A + 36

Equating P' to zero gives;

2A + 36 = 0

2A = -36

A = -36/2

A = -18

Thus;

B = 36 + A

B = 36 - 18

B = 18

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