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Three compounds of carbon, hydrogen, and oxygen exist:

C3H7OH, C3H6(OH)2, and C3H5(OH)3.

Rank the three compounds from lowest to highest boiling points using your prediction of the intermolecular forces exhibited by these three compounds.

Explain your answer.

Respuesta :

jcarl
London dispersion is present, as we can see C3H5(OH)3 is very branched, when a molecule is branched it has a low boiling point due to how compact the surface area is compare to C3H7OH which has a large surface area (in this molecule there is only on branch)
Ver imagen jcarl
mayokunoke

Answer:

From lowest to highest boiling point, we would have;

C3H7OH < C3H6(OH)2 < C3H5(OH)3

Explanation:

Considering the three compounds in question, there is just one type of inter-molecular force that differentiates them and that is the Hydrogen bond. This dipole-dipole bond exists between a hydrogen molecule and an electronegative molecule (oxygen in this case -OH).

There is just one of such bond/force in the first compound, two in the second and three in the last one. The more the hydrogen bond, the more the inter-molecular forces present in the compounds and the higher the boiling point. Thus we have in terms of boiling point;

C3H7OH < C3H6(OH)2 < C3H5(OH)3

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