x = 3
y = 5
(3,5)
I used substitution because It seemed the easiest.
From the second equation I isolated it for Y to get y=20-5x
I plugged this in to the other equation for the Y value to perform substitution.
-7x + 8 (20-5x) = 19
then it's simple algebra
-7× + 160 - 40x = 19
-47x + 160 = 19
subtract 160 from both side and divide both side by -47 to isolate x.
-47x = -141
x=3
then to find Y, simple plug this into one of the equation above. or simply use this one that we already isolated for Y:
y=20-5x
y=20-5 (3)
y=5
hope that helps
