Two urns both contain green balls and red balls. Urn I contains 6 green balls and 4 red balls and Urn II contains 8 green balls and 7 red balls. A ball is drawn from each urn. What is the probability that both balls are red? a. 14/75 b. 7/25 c. 2/75 d. 7/150

From the first urn, since there are 10 balls and 4 of which are red then, the update in the expanssion.

P1 = 4/6 = 2/3

In the second urn, the probability of picking white is 7/15.
Pf = (2/3)(7/15) = 21/81

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agaue agaue · Answer 2 · 2019-10-22T09:39:07+02:00

Answer:

Option A is the correct answer.

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to total number of outcomes,

Urn I contains 6 green balls and 4 red balls and Urn II contains 8 green balls and 7 red balls.

[tex]\texttt{Probability of drawing red ball from Urn 1= }\frac{\texttt{Number of red balls in Urn 1}}{\texttt{Number of balls in Urn 1}}\\\\\texttt{Probability of drawing red ball from Urn 1= }\frac{4}{4+6}=\frac{4}{10}\\\\\texttt{Probability of drawing red ball from Urn 1= }\frac{2}{5}[/tex]

Urn II contains 8 green balls and 7 red balls.

[tex]\texttt{Probability of drawing red ball from Urn 2= }\frac{\texttt{Number of red balls in Urn 2}}{\texttt{Number of balls in Urn 2}}\\\\\texttt{Probability of drawing red ball from Urn 2= }\frac{7}{8+7}=\frac{7}{15}\\\\\texttt{Probability of drawing red ball from Urn 2= }\frac{7}{15}[/tex]

Probability that both balls are red if a ball is drawn from each urn = Probability of drawing red ball from Urn 1 x Probability of drawing red ball from Urn 2

[tex]\texttt{Probability that both balls are red if a ball is drawn from each urn = }\frac{2}{5}\times \frac{7}{15}\\\\\texttt{Probability that both balls are red if a ball is drawn from each urn = }\frac{14}{75}[/tex]

Option A is the correct answer.