A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used = 43.2 mL concentration NaOH = 0.15 M mL H2SO4 = 20.5 mL Notice that H2SO4 releases 2 H+ per mole. What is the concentration of H2SO4? 0.036 M 0.16 M 0.63 M 6.3 M

For the titration we use the equation,
M₁V₁ = M₂V₂
where M is molarity and V is volume. Substituting the known values,
(0.15 M)(43.2 mL) = (2)(M₂)(20.5 mL)
We multiply the right term by 2 because of the number of H+ in H2SO4. Calculating for M₂ will give us 0.158 M. Thus, the answer is approximately 0.16M.

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RomeliaThurston RomeliaThurston · Answer 2 · 2019-05-14T09:53:46+02:00

Answer: The concentration of [tex]H_2SO_4[/tex] comes out to be 0.16 M.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=2\\M_1=?M\\V_1=20.5mL\\n_2=1\\M_2=0.15M\\V_2=43.2mL[/tex]

Putting values in above equation, we get:

[tex]2\times M_1\times 20.5=1\times 0.15\times 43.2\\\\M_1=0.16M[/tex]

Hence, the concentration of [tex]H_2SO_4[/tex] comes out to be 0.16 M.