Respuesta :
[tex]6 \sin \theta - 3 \csc \theta=0
6\sin ^2 \theta - 3=0
2 \sin ^2 \theta -1=0
2 \sin ^2 \theta =1
\sin ^2 \theta = \frac{1}{2}
\sin \theta = \sqrt{\frac{1}{2}}
\sin \theta = \frac{{\sqrt{2}}}{2}
[/tex]