Answer:
a). [tex]\theta=tan^{-1}(\frac{s}{750} )[/tex]
b). θ = 50.19° and θ = 63.43°
Step-by-step explanation:
a). In the figure attached, Space shuttle is at the point A and camera is at point C.
We have to find the expression representing angle θ.
[tex]tan\theta=\frac{AB}{BC}[/tex]
[tex]tan\theta=\frac{s}{750}[/tex]
[tex]\theta=tan^{-1}(\frac{s}{750} )[/tex]
b). we plug in the value s = 900 meters to calculate the value of θ from the given expression.
θ = [tex]tan^{-1}(\frac{900}{750} )[/tex]
θ = [tex]tan^{-1}(1.2)[/tex]
θ = 50.19°
For s = 1500 meters
[tex]\theta=tan^{-1}(\frac{1500}{750} )[/tex]
[tex]\theta=tan^{-1}(2)[/tex]
θ = 63.43°
