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Starchy grain is dominant over sugary corn. If, in a cross between these types, 58 of the progeny are sugary, how many of the progeny should be starchy

Respuesta :

taskmasters

Let us solve first the phenotype of this problem.

Starchy grain = AA (dominant)

Sugary Corn = aa (recessive)

AA x aa = AaAa ; AaAa

     A    A

a  Aa   Aa

a  Aa   Aa

The result of the cross is that the progeny will become heterozygous.

If there is 58 progeny sugary, there will also be 58 starchy. It is 50%.

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