Answer:
-2 is the slope of PS
Step-by-step explanation:
Slope for the given two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is given by:
[tex]\text{Slope} = \frac{y_2-y_1}{x_2-x_1}[/tex]
As per the statement:
Quadrilateral PQRS has vertices at the point P(1,0), Q(3,-1), R(3,-3), and S(2,-2).
We have to find the slope of PS.
Coordinate of P and S are:
P(1, 0) and S(2, -2)
then by using slope formula we have;
[tex]\text{Slope of PS} = \frac{-2-0}{2-1}[/tex]
⇒[tex]\text{Slope of PS} = \frac{-2}{1}[/tex]
⇒[tex]\text{Slope of PS} = -2[/tex]
Therefore, the slope of PS is, -2
