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PLEASE HELP!!!!!!!!!!!!!!
A simple pendulum has a length of 52.1 cm and makes 83.7 complete oscillations in 2.00 min.

(a) Find the period of the pendulum.


(b) Find the value of g at the location of the pendulum.

Respuesta :

MISHAN
Time period is 120/83.7=1.43 s and
g = l / [(T / 2pi)^2] =0.521/[(1.43/2pi)^2]=10 m/s
asuwafohjames

(a) The period of the pendulum is 1.43 seconds

(b) The value of g is 10.2 m/s.

What is the period of a pendulum?

Period is the time taken for a pendulum to complete one oscillation

(a) To calculate the period of the pendulum, we use the formula below.

Formula:

  • T = (t×60)/∅............ Equation 1

Where:

  • t = Total time
  • ∅ = Number of revolution
  • T = Period of the pendulum

From the question,

Given:

  • t = 2
  • ∅ = 83.7

Substitute the given values into equation 1

  • T = (2×60)/83.7
  • T = 120/83.7
  • T = 1.43 seconds.

(b) To calculate the value of g, we use the formula below.

Formula:

  • T = 2π√(L/g).............. Equation 2

Where:

  • L = Length of the pendulum
  • g = acceleration due to gravity
  • T = Period of the pendulum
  • π = pie.

From the question,

Given:

  • L = 52.1 cm = 0.521 m
  • T = 1.43 seconds
  • π = 3.14

Substitute these values into equation 2 and solve for g

  • 1.43 = 2(3.14)√(0.521/g)
  • 1.43/6.28 = √(0.521/g)
  • 0.226 = √(0.521/g)
  • 0.521/g = 0.226²
  • 0.521/g = 0.051
  • g = 0.521/0.051
  • g = 10.2 m/s²

Hence, (a) The period of the pendulum is 1.43 seconds (b) The value of g is 10.2 m/s.

Learn more about the period of a simple pendulum here: https://brainly.com/question/14456407

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