Jessie6754
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Give the name of the following molecule. A compound with a total of seven carbons with a double bond and the rest single bonds. There is a chain of four carbons along the bottom with a double bond between the third and fourth carbon when counting from left to right. There is a propyl group branching off of the third carbon from the left.

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(1) compound with seven carbons with double bond and the rest single bond :
                                      HEPTENE
(2) four carbons with a double bond between the third and the fourth carbon:
                                     1-BUTENE
(3) Propyl group branching from the third carbon from the left:
                                     3-Propyl heptene
sebassandin

Answer:

2-ethyl-pentene.

Explanation:

Hello,

In this case, following the given indications, the molecule is shown of the attached picture. Thus, the double bond is placed as well as the propyl radical. In such a way, the resulting molecule is 2-ethyl-pentene since the longest chain has five carbons and at the second carbon there is an ethyl radical. Moreover, the double bond makes the molecule an alkene, finishing with "ene".

Best regards.

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