A sample of gas is transferred from a 75 ml vessel to a 500.0 ml vessel if the initial pressure of the gas is 145 atm and if the temperature is held constant what is the pressure of the gas sample in the 500.0 ml vessel ?

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Answer: The final pressure of the gas sample is 21.75 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=145atm\\V_1=75mL\\P_2=?atm\\V_2=500.0mL[/tex]

Putting values in above equation, we get:

[tex]145atm\times 75mL=P_2\times 500.0mL\\\\P_2=\frac{145\times 75}{500.0}=21.75atm[/tex]

Hence, the final pressure of the gas sample is 21.75 atm

Considering the Boyle's law, the final pressure is 21.75 atm.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

Boyle's law is a gas law that states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.

Mathematically, Boyle's law is the product of pressure times volume always equal to the same value:

P×V= k

Being the initial state 1 and the final state 2, it is true:

P1×V1= P2×V2

In this case, you know:

  • P1= 145 atm
  • V1= 75 mL
  • P2= ?
  • V2= 500 mL

Replacing:

145 atm× 75 mL= P2× 500 mL

Solving:

[tex]P2=\frac{145 atmx75 mL}{500 mL}[/tex]

P2=21.75 atm

In summary, the final pressure is 21.75 atm.

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