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41 car a, moving in a straight line at a constant speed of 20. meters per second, is initially 200 meters behind car b, moving in the same straight line at a constant speed of 15 meters per second. how far must car a travel from this initial position before it catches up with car b?

Respuesta :

nourhanashraf9
according to motion 2nd equation
d=vit+1/2at^2
200=20t+0
t=10 sec
....
the second car
let its displacement until meeting point be x
d=vit+1/2 at^2
x=15t
....
total displacement
d=200+x ..(substituting x)
d=200+15×10
=350m

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