To what temperature must a balloon, initially at 25°c and 2.00 l, be heated in order to have a volume of 6.00 l?

Question

24-04-2017
Chemistry

contestada

To what temperature must a balloon, initially at 25°c and 2.00 l, be heated in order to have a volume of 6.00 l?

Respuesta :

Otras preguntas

While ________ refers to works that realistically depict easily identifiable objects and events in a pretentiously vulgar, awkward, sentimental, and often obsce

Matt works for a sports marketing firm. He feels that he has been treated unfairly by the organization. He helped three other employees organize a series of suc

Please help! If you need a close up please don’t hesitate to ask!

Which of the following is true? A) Nutritional Labeling and Education Act gives definitions for terms such as "fresh," " light," "low-fat," and "reduced-calorie

Rawat bhata nuclear power plant is situated in

Product X-547 is one of the joint products in a joint manufacturing process. Management is considering whether to sell X-547 at the split-off point or to proces

The two most internationally recognized American writers in the 1820s were______. A) Washington Irving and James Fenimore Cooper. B) Edgar Allan Poe and Charles

As a therapist, June follows basic Freudian principles, but is more likely to focus on the present rather than the past, and takes a more directive role in ge

What was a major result of George Washington eventually allowing slaves in the army? Over 300,000 slaves received freedom after serving in the army The added nu

samantharobinso1 samantharobinso1 · Answer 1 · 2017-04-24T16:39:22+02:00

samantharobinso1 samantharobinso1

24-04-2017

V1 = 2.00 L
T1 = 25 + 273 = 298 K
V2 = 6.00 L
T2 = ?
Assuming the pressure is to remain constant, then
V1/T1 = V2/T2
T2 = T1V2/V1 = (298)(6)/(2) = 894 deg K

Answer Link

kobenhavn kobenhavn · Answer 2 · 2019-04-07T14:11:52+02:00

Answer: 894 K

Solution :

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex] (At constant pressure and number of moles)

The combined gas equation is,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1[/tex] = initial volume of gas = 2.00 L

[tex]V_2[/tex] = final volume of gas = 6.00 L

[tex]T_1[/tex] = initial temperature of gas = [tex]25^oC=273+25=298K[/tex]

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above equation, we get the final temperature of the gas

[tex]\frac{2.00L}{298K}=\frac{6.00L}{T_2K}[/tex]

[tex]T_2=894K[/tex]

Therefore, the temperature must be 894 K in order for balloon to have a volume of 6.00 L.