Lilly has a box of chocolates.
There are 12 chocolates in the box and there is an assortment of white, milk and dark chocolates.
There are 3 white chocolates, 4 milk chocolates and the rest are dark chocolates.
What is the probability that Lilly first chooses a dark chocolate from the box?

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Question: What is the probability that Lilly first chooses a dark chocolate from the box?

Answer: 3 + 4 = 7.
12 - 7 = 5.
There is a probability of 5/12.

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Answer:

The probability is [tex]\frac{5}{12}[/tex] or [tex]41.66%[/tex] chance (rounded up to the near .01)

Step-by-step explanation:

If there are 12 chocolates, 3 white chocolates, and 4 milk chocolates, we need to calculate the amount of dark chocolates.

12 - 3 = 9

9- 4 = 5

So there are 5 dark chocolates.

Now we have to turn it into a fraction.

5 dark chocolates out of 12 chocolates is [tex]\frac{5}{12}[/tex].

[tex]\frac{5}{12}[/tex] = 41.666666666667

41.666666666667 = 41.66

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