Respuesta :
[tex]m + 5n; \\ m = 1, \\ n = 4 \\ ======= \\ 1+5 \cdot4= \\ 1+20= \\ \boxed{21}
[/tex]
If "m" = 1 and If "n" = 4
Your problem becomes↓[tex]1 + 5(4) [/tex]
[tex]5(4) = 20 [/tex]
[tex]1 + 20 = 21 [/tex]
Therefore your answer is: [tex]21 [/tex]
Just do PEMDAS
[tex]Parentheses [/tex]
[tex]Exponents [/tex]
[tex]Multiplication [/tex]
[tex]Division [/tex]
[tex]Addition [/tex]
[tex]Subtraction [/tex]
From the looks of it we have used the "addition " and "multiplication" method of the PEMDAS strategy
Your problem becomes↓[tex]1 + 5(4) [/tex]
[tex]5(4) = 20 [/tex]
[tex]1 + 20 = 21 [/tex]
Therefore your answer is: [tex]21 [/tex]
Just do PEMDAS
[tex]Parentheses [/tex]
[tex]Exponents [/tex]
[tex]Multiplication [/tex]
[tex]Division [/tex]
[tex]Addition [/tex]
[tex]Subtraction [/tex]
From the looks of it we have used the "addition " and "multiplication" method of the PEMDAS strategy